《数值计算方法》课后题答案(湖南大学出版社(12)
发布时间：2021-06-05
湖南大学出版社《数值计算方法》课后题答案
14
习题三
1．1分别用高斯消元法和列选主元法解方程组（精确到小数点后四位）：
123
123
123
0.26410.17350.86420.7521
0.94110.01750.14630.6310
0.86410.42430.07110.2501
x x x
x x x
x x x
++=-
⎧⎫
⎪⎪
-+=
⎨⎬
⎪⎪
--+=
⎩⎭
解：高斯消元法：
()
0.26410.17350.86420.7521
|0.94110.01750.14630.6310
0.86410.42430.0710.2501
A b
-
⎛⎫
⎪
=-
⎪
⎪
--
⎝⎭
=
0.2641 0.1735 0.8642 -0.7521
0 -0.6358 -2.9332 3.3111
0 0.1434 2.8986 -2.2107
⎛⎫
⎪
⎪
⎪
⎝⎭
0.2641 0.1735 0.8642 -0.7521
0 -0.6358 -2.9332 3.3111
0 0 2.2372 -1.4640
⎛⎫
⎪
= ⎪
⎪
⎝⎭
T
( 0.7315, -2.1889, -0.6544)
x=
高斯列选主元消元法
()
0.26410.17350.86420.7521
|0.94110.01750.14630.6310
0.86410.42430.0710.2501
A b
-
⎛⎫
⎪
=-
⎪
⎪
--
⎝⎭
0.94110.01750.14630.6310
0.26410.17350.86420.7521
0.86410.42430.0710.2501
-
⎛⎫
⎪
=-
⎪
⎪
--
⎝⎭
0.9411 -0.0175 0.1463 0.6310
0 0.1784 0.8231 -0.9292
0 -0.4404 0.2054 0.8295
⎛⎫
⎪
= ⎪
⎪
⎝⎭
0.94110.01750.14630.6310
0 -0.4404 0.2054 0.8295
0 0.1784 0.8231 -0.9292
-
⎛⎫
⎪
= ⎪
⎪
⎝⎭
0.9411-0.01750.1463
0-0.44040.20540.8295
000.9064-0.
5931
⎛⎫
⎪
= ⎪
⎪
⎝⎭
()
x=0.7315, -2.1889,-0.6544 T
2．分别用高斯消元法和列选主元法解方程组
上一篇：房地产开发成本控制全[1]
下一篇：班级财产、物资领取登记表
