中考数学压轴题详解—圆(6)
发布时间:2021-06-08
发布时间:2021-06-08
复习圆
(3)证明:连结OC交BD于G由(2)得四边形OBCD是菱形, ∴OC BD且OG GC. ···························································································· 8分 又已知OB=BH , ∴BG∥CH. ········································································ 9分 ∴ OCH OGB 90 , ∴CH是⊙O的切线. ················································· 10分
5 解: (1)添加 AB=BD ····································································································· 2分
∴∠BDE =∠BCD ·∵AB=BD ∴ ············································································ 3分 AB=BD又∵∠DBE =∠DBC ∴△BDE∽△BCD
BDBE
································································································································ 4分 BCBD
的中点 ·(2)若AB∥DO,点D所在的位置是BC···························································· 5分
∵AB∥DO ∴∠ADO =∠BAD ·················································································· 6分
=DC ·∵∠ADO =∠OAD ∴∠OAD =∠BAD ∴DB······················································· 7分
(3)在(1)和(2)的条件下,.
=DC ∴∠∵ BDA =∠DAC ∴ BD∥OA AB=BD
又∵AB∥DO ∴四边形AODB是平行四边形 ················································· 9分 ∵OA=OD ∴平行四边形AODB是菱形 ······················································ 10分
6 解:(1)FB=FE ,PE=PA ···················································································· 2分
(2)四边形CDPF的周长为
FC+CD+DP+PE+EF=FC+CD+DP+PA+BF ·········································· 3分
=BF+FC+CD+DP+PA ········································ 4分 =BC+CD+DA ··············································· 5
分 =
3= ················································· 6分
(3)存在.
7分
OF,则 若BF FG CF
BFCF
OFFG
BFCF
∵ cos∠OFB= ,cos∠GFC=
OFFG
∴ ∠OFB=∠GFC
又 ∵ ∠OFB=∠OFE
∴ ∠OFE=∠OFB=∠GFC=60 ······································································· 8分 ∴ 在Rt△OFB中 FE=FB=∴ 在Rt△GFC中
CG
=CF
tan GFC CF tan60 1tan60 6∴ DG CG CD
6 ∴ DP DG ··········································· 9
分 tan PGD DG tan30 3 ∴
AP AD DP 3 3 ··············································· 10分
京翰教育1对1家教 /
OB
=1
tan60
上一篇:WLAN故障排错综合指导