中考数学压轴题详解—圆(6)

发布时间:2021-06-08

复习圆

(3)证明:连结OC交BD于G由(2)得四边形OBCD是菱形, ∴OC BD且OG GC. ···························································································· 8分 又已知OB=BH , ∴BG∥CH. ········································································ 9分 ∴ OCH OGB 90 , ∴CH是⊙O的切线. ················································· 10分

5 解: (1)添加 AB=BD ····································································································· 2分

∴∠BDE =∠BCD ·∵AB=BD ∴ ············································································ 3分 AB=BD又∵∠DBE =∠DBC ∴△BDE∽△BCD

BDBE

································································································································ 4分 BCBD

的中点 ·(2)若AB∥DO,点D所在的位置是BC···························································· 5分

∵AB∥DO ∴∠ADO =∠BAD ·················································································· 6分

=DC ·∵∠ADO =∠OAD ∴∠OAD =∠BAD ∴DB······················································· 7分

(3)在(1)和(2)的条件下,.

=DC ∴∠∵ BDA =∠DAC ∴ BD∥OA AB=BD

又∵AB∥DO ∴四边形AODB是平行四边形 ················································· 9分 ∵OA=OD ∴平行四边形AODB是菱形 ······················································ 10分

6 解:(1)FB=FE ,PE=PA ···················································································· 2分

(2)四边形CDPF的周长为

FC+CD+DP+PE+EF=FC+CD+DP+PA+BF ·········································· 3分

=BF+FC+CD+DP+PA ········································ 4分 =BC+CD+DA ··············································· 5

分 =

3= ················································· 6分

(3)存在.

7分

OF,则 若BF FG CF

BFCF

OFFG

BFCF

∵ cos∠OFB= ,cos∠GFC=

OFFG

∴ ∠OFB=∠GFC

又 ∵ ∠OFB=∠OFE

∴ ∠OFE=∠OFB=∠GFC=60 ······································································· 8分 ∴ 在Rt△OFB中 FE=FB=∴ 在Rt△GFC中

CG

=CF

tan GFC CF tan60 1tan60 6∴ DG CG CD

6 ∴ DP DG ··········································· 9

分 tan PGD DG tan30 3 ∴

AP AD DP 3 3 ··············································· 10分

京翰教育1对1家教 /

OB

=1

tan60

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