运营管理2考试习题(2)

标准差，再根据第二步算出的一个数查表找寻z值，最后得出x。

例题：McDonald has to decide how many seats to provide in a new McDonald in Mian Yang, the manager know the demand in Mian Yang is normally distributed with an average of 200 seats per day and a standard deviation of 15. One day, the McDonald has to turn away a customer because seats are all occupied, it loses the gross margin on the seat of 40RMB. They also know that if the McDonald has one seat unoccupied on a particular day, the cost is estimated to be 10RMB。What’s the optimal number of seats of the McDonald?

答案：P(D>C*)=10/(40+10) =0.2

F(C*)=1- P(D>C*)=1-0.2=0.8

Z=(C*-200)/15

查表所得：Z=0.85

C*=213

三、optimal overbooking level 超额预定水平 P306—307

P(D L) CS CS C0

注意与前面一个公式相区分哦~

四、Gravity models in retail management （huff model）引力模型P330—332

Sj

Tijb（S代表商场的规模，T代表从地点i到设施j行进的时间或距离，b是参数） Pij nSj Tj 1b

ij

注意：在公式里面下面求和的公式是由原本就有的商场和要选择的商场的和，比如学校旁边本来就有2家商场A和B，但是现在要增加一个商场，选址在C或D点，那么选择C或者是D就是一个问题，要先分别算出C或者D的P值，然后分别用P值*消费者人数*平均每人花费，看哪个算出来的值大就选择哪个。在这个P值的计算里，下面求和的是本来就存在的的A和B两个再加上C或者是D。

例题：We already have 3 KFCs in our city (A,B,C), now they want bring a new one , where should they build? They have 3 choices (D,E,F). The city has 20000 people, each spending 800 RMB a year for KFC. SA=1500 TA=5 SB=360 TB=3 SC=800 TC=2 SD=900 TD=5 SE=800 TE=4 SF=900 TF=3 b for A,B,F = 2 b for C,D,E = 1 （答案米有，很简单自己做）

五、Location models 选址模型P328—329

wight*score

a 1n

weight

n 1n 很简单 一般考选择题

六、1、What is yield management? P304---305

Answer：the process of allocating the right type of capacity to the right type of customer at the right price so as to maximize revenue or yield.

2、what’s the yield?