int a, b, c;

long n, i, t, s = 0;

printf("Input n(27<n<=77):\n");

scanf("%d", &n);

for (a = 0; 4 * a <= n; a++)

for (b = 0; 4 * a + 3 * b <= n; b++)

for (c = 0; 4 * a + 3 * b + c / 2 <= n; c += 2)

if (4 * a + 3 * b + c / 2 == n && c%2 == 0 && a+b+c==36)

{

printf("men=%d,women=%d,children=%d\n", a, b, c);

}

}

6.4

编程输出某年某月有多少天（考虑到闰年）。（5分）

题目内容：

从键盘输入一个年份和月份，输出该月有多少天（考虑闰年），用switch语句编程。

#include<stdio.h>

int main()

{int year,month,day;

printf("Input year,month:\n");

scanf("%d,%d",&year,&month);

switch(month)

{

case 1: day=31;break;

case 2: day=28;break;

case 3: day=31;break;