2013澳大利亚高考数学试题答案(19)
发布时间:2021-06-08
发布时间:2021-06-08
STANDARD INTEGRALS
n
xdx 1 dx ax edx
=
1n+1
x , n ≠ 1; x ≠0, if n <0n +1
=ln x, x >0
1ax= e , a ≠0 1
= sinax, a ≠01
= cosax, a ≠0
1
= tanax, a ≠0
cosax dx
sin ax dx
2
sec ax dx
1 secax tanax dx = secax, a ≠0
1
dx 22 a +x 1
dx
2 a x 2 1
dx
x2 a2
dx 1 x
= tan 1, a ≠0 1 x =sin , a >0, a <x <a
2
=lnx + x 2 a , x >a>0
((
) )
2=lnx + x 2+a
NOTE : ln x =loge x , x >0
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