南京工业大学-化工原理期末试卷及答案(4)

∵y1=0.03 x1=0.03 ∴m=1

(L/G)min=(y1-y2)/(y1/m)=0.95

L/G=m/S=1/0.8=1.25

∴(L/G)/( (L/G)min)=1.316

x1=(y1-y2)/( L/G)=0.0228

NOG=1/(1-S)ln[(1-S)y1/y2+S]=7.843

[四] j07d20122

(1)∵FXF=DXD+WXW

∴XW=0.05

(2)yD=xD=0.83

x0=0.83/(2.5-1.5*0.83)=0.66

∵y1=R*x0/(R+1)+ xD/(R+1)

∴R=1.83

(3)V’=V=(R+1)D=12900kg/h

(4)xq=xF=0.44 yq=2.5*0.44/(1+1.5*0.44)=0.663 Rmin=(xD-yq)/(yq-xq)=0.749

[五] j09b15028

τA＝GC(X1-X0)rw/[αA(t-tw)]= Wrw/[αA(t-tw)] ｒW＝2491.27 －2.30285tW

τB/τA= [rBw/ (t-tBw)]/ [rAw/ (t-tAw)]=0.20217 τB =0.20217h

[六] j07d20107

DXD/FXF=0.8

∴D/F=0.533

D/F=(XF-XW)/(XD-XW)=0.533

∴XW=0.0857

L’/V’=F/D=1.876

W/V’=W/D=(F-D)/D=0.876

ym+1= (L’/V’)xm-(W/V’)xw=1.876 xm -0.0751 yw=αxw/[1+(α-1)xw]=0.22

x1=(yw+0.0751)/1.876=0.157

y1=xD=0.3

ｘ*1=y1/[α-(α-1)y1]=0.125

ＥML=(ｘn-1-ｘn)/ (ｘn-1-ｘ*n)=(ｘF-ｘ1)/ (ｘF-ｘ*1)=0.573