高一物理牛顿运动定律综合测试题(4)

16：Fcosθ

—μFN = 0 FN + Fsinθ—mg = 0

μ = 1/3 a = μg

x = 15m TNA FNA + FTsinθ—G1 = 0 FT = 227.3N F — μFNB — FTcosθ=0

FTsinθ + FNB — G1 — G2 = 0 F = 413.6N 18.

kx1 = mAgsinθ kx2 = mBgsinθ

F— kx2 — mAgsinθ = mAa a = (F— mAgsinθ— mBgsinθ)/mA d = x1 + x2 = (mA + mB)gsinθ/k