系列文档为华南理工大学电机学配套教程的课后习题讲解及详细答案。

=I +I +I =10+3 j4+j5=13+j1=13.04∠4.4D IUU+U U0 =a2I +aI +I =10∠240D+(3 j4)∠120D+j5IVU+U U0

....= 5 j8.66+1.964+j4.598+j5= 3.036+j0.938=3.18∠162.83 =aI +a2I +I =10∠120D+(3 j4)∠240D+j5IWU+U U0

.....= 5+j8.66 4.964 j0.598+j5= 9.964+j13.062=16.43∠127.34

DD

= =220∠0，U2．解：UUV

D

2202

=0 ∠ 120D，UW

=1(U +aU +a2U )=1(220∠0D+220∠ 120D∠120D+0)=125.19∠0D UU+UVW

332 =1(U +a2U +aU )=1(220∠0D+220∠ 120D∠240D+0)=65.3∠43.45D UU UVW

332 =1(U +U +U )=1(220∠0D+220∠ 120D+0)=65.3∠ 43.45D UU0UVW

332 =125.19∠ 120D U =125.19∠120D UV+W+ =65.3∠163.45D U =5.3∠ 76.55D UV W =U =U =65.3∠ 43.45D UV0W0U0