武汉大学版无机化学课后习题答案(9)
发布时间:2021-06-06
发布时间:2021-06-06
△rG m =△rG θ
m + RTln K θ=kJ ·mol 1- Ⅱ K θ=22
52.1507.0=0.111 △rG m =△rG θ
m + RTln K θ=3610.249—17782.590=—14.2kJ ·mol 1- Ⅲ K θ=22
266.176.0=0.360 △rG m =△rG θm + RTln K θ=3610.249+(—8264.670)=—4.7kJ ·mol 1- Ⅳ K θ=1
△rG m =△rG θm + RTln K θ=3610.249=3.6kJ ·mol 1-
Ⅴ K θ=22
76.0266.1=2.775 △rG m =△rG θm + RTln K θ=11.9kJ ·mol 1-
Ⅵ K θ=22
507.052.1=8.988 △rG m =△rG θm + RTln K θ=21.4kJ ·mol 1-
Ⅶ K θ=22
253.0773.1=49.111 △rG m =△rG θm + RTln K θ=35.1kJ ·mol
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