哈工大版线性代数与空间解析几何课后题答案(4)

D ( 1)t(1234)a11a22a33a44 ( 1)t(1243)a11a22a34a43 ( 1)t(2134)a12a21a33a44

( 1)

t(2143)

a12a21a34a43

a11a22a33a44 a11a22a34a43 a12a21a33a44 a12a21a34a43 从而

a11a21a12a33

a22a43

a34a44

(a11a22 a12a21)(a33a44 a34a43)

a11a22a33a44 a11a22a34a43 a12a21a33a44 a12a21a34a43 D 6．计算

a0

(1)

10

121102111

；

2 144 2 1110

123 n

xa a

110 0

ax a

； (4) Dn 101 0； (3) Dn

aa x

100 1

a00 111 10a0 0 11 1

(5) Dn 00a 0； (6) Dn 1 1 1.

100 a11 1a305

a30

按第4 按第3 0b02a34 4

解：(1) ( 1)d0b0( 1)3 3dc abcd.

12c3行展开0b列展开

12c

000d121112111211021110211102111

(2)

2 14403660366 2 11100331200 36

3b2000c052

； (2) 3d

·4·