}

else if ('0'=<str[i]&& str[i]<='9')

{

++digit;

}

else if (str[i]= =' ' )

{

++space;

}

else

++other;

}

printf("英文字符数:%d\n", letter);

printf("数字字符数:%d\n", digit);

printf("空格数:%d\n", space);

printf("其他字符数:%d\n", other);

}

答案：

1）define ARR_SIZE = 80 改为 define ARR_SIZE 80

2）if (a=<str[i]<=z && A=<str[i]<=Z)

改为if ( a =<str[i]&& str[i]<= z || A =<str[i]&&str[i]<= Z )

6、任意输入一个字符串，在星期表中查找该字符串，若找到，则打印 “已找到”,否则打印 “没找到”。

#include<string.h>

main()

{

int i;

int findFlag;

char x[10];

char weekDay[7][10]= {

"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"}; findFlag=0；

printf("请输入一个字符串:");

scanf("%s",x);

for (i=0; i < 7 && !findFlag; i++)

{

改为： if （strcmp(x ，weekDay[i])= =0） {