10 因为6x ＜f x 精馏段理论板 n=5 '

160.337x x == ''

211.4120.0290.447y x =-=

2

22'

'2''0.246(1)

y x y y ==+2.475- ''

321.4120.0290.318y x =-=

3

33'

'3''0.159(1)

y

x y y ==+2.475- ''

431.43340.0330.195y x =-=

4

44''4''0.089(1)

y x y y ==+2.475- ''

541.4120.0290.097y x =-= 5

55''5''0.042(1)

y x y y ==+2.475-<w x 所以提留段理论板 n=4

全塔效率的计算（查表得各组分黏度1μ=0.269，2μ=0.277）

12(1)0.4090.269(10.409)0.2770.274m F F x x μμμ=+-=⨯+-⨯= 0.170.616lg T m E μ=-=0.170.616lg0.27452%-≈ 捷算法求理论板数

min 11/ln {ln[()()]}19.89818.8981W

D m D W

x x N x x α-=-=-=-

由公式 0.5458270.5914220.002743/Y X X =-+ min 2.92 1.46

0.3741 3.92R R X R --===+

代入 Y=0.488 由min

0.3165,102N N N N -==+

min,1111/ln {ln[()()]}1 4.92551D

F

D F

x x N x x α-=-=≈-

0.974

10.24

1.14ln[()()]1 4.44510.9740.24-=-=≈-

精馏段实际板层数