Sat 数学历年真题

7

Remainder is 0. k can’t be 7. Let’s try k = 8. 1 r 1

7

8 is better, but we’re not there yet. What about 9? 1 r 2 7

See the pattern here? Every time we increase the dividend* by 1, the remainder increases by 1. We can continue going all the way up, but hopefully we see that 13 will give us a remainder of 6 as below. 1 r 6

7 Bingo. k must be 13 (or any multiple of 13).

* Not the most exciting topic, but know your terminology. A dividend is the number under the division sign (in this case 13), and the divisor is what you are dividing by (in this case7).

Use k in the second equation, k + 2. k + 2 = ? 13 + 2 = 15

Finish up. What’s the question asking again? The remainder when k +2 is divided by 7.

2 r 1 That’s the answer! 7 1

B is the correct answer. Test 1 Section3 Question 12

Graphing Data Problem. Take a second to absorb what’s shown in the table. Forget about the answers for a second.

Look for a pattern in the table of data. See that when Depth goes up, Pressure Now look at the graphs.