有机化学(英文影印版)-chapter+5+stereochemistry+chiral+molecul...
发布时间:2024-11-02
发布时间:2024-11-02
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Chapter 5Stereochemistry: Chiral Molecules
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Examples of Constitutional Isomers
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Examples of Stereoisomers
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Subdivision of Isomers
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Enantiomers and Chiral Molecules Enantiomers: stereomers that are nonsuperposable mirror images of each other
Chiral Molecule: a molecule that is not superposable on its mirror image. Chiral molecules have handedness and are capable of existing as a pair of enantiomers Achiral molecule: a molecule that is superposable on its mirror image Chirality: the property of having handedness
Hands, ears, shoes
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Examples of Enantiomersstereocenter carbon has 4 non-equivalent groups attachedHandedness center Handedness carbon
Its mirror image is non-superposable
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Tests for Chirality In Molecules Has no internal plane of symmetry Has at least one stereocenter carbon
Its mirror image is non-superposable (not identical) Achiral molecule: the molecule can be superposable on its mirror image (it has planar symmetry, at least two identical groups may attached to the center carbon)
2-butanol Chiral molecule
Achiral molecule Symmetric plane
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
unsymmetrical operation — compare molecular geometry Interchange any two groups of the stereocenter carbon, will produce its enantiomer (unsymmetrical operation) exchange
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Examples of Achiral Molecules2-Propanol
All molecules with a plane of symmetry are achiral.
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Requirements For Enantiomeric Pairs Non-superimposable mirror images of one another (exhibit chirality) Must have only one stereocenter carbon Must not have a plane of symmetry The two rotate plane polarized light in opposite directions but to the same degree (optically active) Two will have opposite configurations
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Biological Importance of Chirality Amino Acids-19/20 are chiral, all left handed Carbohydrates are chiral and right handed DNA is chiral and right handed Seashells coil always right handed Honeysuckle winds left handed Bindweed winds right handed
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Physiological Differences Between Enantiomeric Pairs Limonene– One enantiomer(R) = odor of oranges – One enantiomer(S) = odor of Lemons
Carvone– One enantiomer = odor of caroway seeds – One enantiomer = odor of spearmint Thalidomide– One enantiomer (R) cures morning sickness – One enantiomer (S) causes birth defects
Conversion of one enantiomer in vivo is slow but certain
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Nomenclature of Enantiomers: — the (R-S) system Locate stereocenter carbon Establish Priority of each atom directly bonded to stereocenter using Cahn-Ingold-Prelog rules Project atom of lowest priority to back of molecule
Trace through other three atoms beginning with highest to lowest If trace rotates clockwise (to the right) then configuration is “R” ; If trace rotates counter clockwise (left) then configuration is “S” For 3-D structures if lowest priority is in front, determine configuration as above and then reverse it.
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Cahn-Ingold-Pre
log Priority Rules Atoms directly bonded to stereocenter will have priority based on atomic number If two atoms have same atomic number (isotopes) then mass number decides If two atoms are same (in A.N. and mass number) then atoms directly attached to them will decide by totaling atomic number of all atoms For atoms with multiple bonding multiply atom with single bonds:
-CH=CH2 is higher Than —CH(CH3)2 Assigning Configuration of 3-D formulas Determining whether two molecules are identical or entiomers (Problems 5.13 and 5.14)
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Example of nomenclature by R-S System
(R)
? Do the problem 5.9, p197 ? Do the problem 5.12(c), p198
ORGANIC CHEMISTRY有机化学英文影印版第八版PPT
Compare between two compounds — sample problemApproach 3: Naming by R-S
identical ?
Approach 1: Hold the molecule by one group, rotate the other groups until at least one group is in the same place
Approach 2: invert the configuration by exchange of two groups