尺寸链公差叠加分析
发布时间:2021-06-06
发布时间:2021-06-06
GD&T Tolerance Stack-up Analysis Exercises Answer尺寸链公差叠加分析练习答案
奥曼克公司– Omnex Inc.
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部分培训目录ISO/TS系列: (RABQSA批准) TS16949内审员/主任审核员 ISO 9000内审员/主任审核员 ISO 14000内审员/主任审核员 OHSAS 18001 ISO 17025 QS-9000 TE核心工具类: APQP FMEA (PFMEA& DFMEA) PPAP SPC MSA福特系列 QOS MMOG Q14
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© Copyright 2008 Omnex–奥曼克公司
Chapter#3 Worst Case Linear Tolerance Stack-up极限公差叠加分析–线性公差
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© Copyright 2008 Omnex–奥曼克公司
Chapter#3 Worst Case Linear Tolerance Stack-up (极限公差叠加分析-线性公差)Exercise#3.1参照下图完成计算A-B最大最小距离 Answer(答案): Min=0.6, Max=3
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© Copyright 2008 Omnex–奥曼克公司
Chapter#3 Worst Case Linear Tolerance Stack-up (极限公差叠加分析-线性公差)Exercise#3.2参照下图完成计算A-B最大最小距离 Answer(答案): Min=6, Max=14.85
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Chapter#3 Worst Case Linear Tolerance Stack-up (极限公差叠加分析-线性公差)Exercise#3.3参照下图完成计算A-B最大最小距离 Answer(答案): Min=7, Max=2
2.75
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© Copyright 2008 Omnex–奥曼克公司
Chapter#3 Worst Case Linear Tolerance Stack-up (极限公差叠加分析-线性公差)Exercise#3.4参照下图完成计算A-B最大最小距离 Answer(答案): Min=58.9, Max=73.1
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© Copyright 2008 Omnex–奥曼克公司
Chapter#3 Worst Case Linear Tolerance Stack-up (极限公差叠加分析-线性公差)Exercise#3.5参照下图完成计算A-B最大最小距离 Answer(答案): Min=3.7, Max=8.5
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© Copyright 2008 Omnex–奥曼克公司
Chapter#3 Worst Case Linear Tolerance Stack-up (极限公差叠加分析-线性公差)Exercise#3.6参照下图完成计算A-B最大最小距离 Answer(答案): Min=-3.7, Max=15.5
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Chapter#4 Geometric Dimensioning and Tolerancing Stack-up几何尺寸和公差叠加
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Chapter#4 GD&T Stack-up (几何尺寸和公差叠加)Exercises#4.1计算A-B最大最小距离 Answer(答案): Min=-0.8, Max=15.8
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Chapter#4 GD&T Stack-up (几何尺寸和公差叠加)Exercises#4.2计算A-B最大最小距离Answer(答案): Min=0.7, Max=14.3
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Chapter#4 GD&T Stack-up (几何尺寸和公差叠加)Exercises#4.3计算A-B最大最小距离 Answer(答案): Min=1.72, Max=10.08
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Chapter#6 Tolerance Stack-up with Trigonometry公差叠加三角分析
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Chapter#6 Tolerance Stack-up with Trigonometry (公差叠加三角分析)Exercise#6.1参照图纸计算A-B最大最小值Answer(答案): Min=0.0905, Max=0.2855
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© Copyright 2008 Omnex–奥曼克公司
Chapter#6 Tolerance Stack-up with Trigonometry (公差叠加三角分析)Exercise#6.2参照图纸计算A-B最大最小值 Answer(答案): Min=0.0777, Max=0.2987
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© Copyright 2008 Omnex–奥曼克公司
Chapter#6 Tolerance Stack-up with Trigonometry (公差叠加三角分析)Exercise#6.3参照图纸计算A-B最大最小值 Answer(答案): Min=0.0498, Max=0.4286
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Chapter#9 Statistic Tolerance Stack-up统计公差叠加分析
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Chapter#9 Statistic Tolerance Stack-up (统计公差叠加分析)Exercise#9.1参照图纸计算A-B统计公差 Answer(答案): Min=0.7, Max=2.9
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© Copyright 2008 Omnex–奥曼克公司
Chapter#9 Statistic Tolerance Stack-up (统计公差叠加分析)
Exercise#9.2参照图纸计算A-B统计公差 Answer(答案): Min=10.205, Max=19.545
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Chapter#9 Statistic Tolerance Stack-up (统计公差叠加分析)Exercise#9.3参照图纸计算A-B统计公差 Answer(答案): Min=61.11, Max=70.89
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© Copyright 2008 Omnex–奥曼克公司
Chapter#9 Statistic Tolerance Stack-up (统计公差叠加分析)Exercise#9.4参照图纸计算A-B统计公差 Answer(答案): Min=4.3, Max=7.9
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Chapter#10 Advanced Tolerance Stack-up高级公差叠加
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Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Advanced Tolerance Stackup Cases
FIGURE 16.1 Enclosure assembly for 16—18.
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Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Advanced Tolerance Stackup Cases
FIGURE 16.2 Ground plate for 16—18: Option 1
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© Copyright 2008 Omnex–奥曼克公司
Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Advanced Tolerance Stackup Cases
FIGURE 16.3 Ground plate for 16—18: Option 2.
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© Copyright 2008 Omnex–奥曼克公司
Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Advanced Tolerance Stackup Cases
FIGURE 16.4 Ground plate for 16—18: Option 3.
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© Copyright 2008 Omnex–奥曼克公司
Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Advanced Tolerance Stackup Cases
FIGURE 16.5 Enclosure for 16— 18: Option 1.
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© Copyright 2008 Omnex–奥曼克公司
Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Advanced Tolerance Stackup Cases
FIGURE 16.6 Enclosure for 16— 18: Option 2.
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© Copyright 2008 Omnex–奥曼克公司
Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Advanced Tolerance Stackup Cases
FIGURE 16.7 Enclosure for 16- 18: Option 3.
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© Copyright 2008 Omnex–奥曼克公司
Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Advanced Tolerance Stackup Cases
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© Copyright 2008 Omnex–奥曼克公司
Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Advanced Tolerance Stackup Cases
FIGURE 16.9 Cover for 16-18.
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Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Exercise 10.1 Screw Thread Depth Tolerance Stackup: Option 1 Determine if the M4 screws bottom out in the threaded holes.Answer(答案): Min=0.9, Max=4.5
Exercise 6.1. Screw Thread Depth Tolerance Stackup Determine if the M4 screws bottom out in the threaded holes. Extra data: M4washer thickness= 1.2± 0.1. M4 x 8 socket head cap screw length= 8± 0.2 (from vendor drawing). Length is from bottom of head to end of screw.
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Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Exercise 10.2 Cover Fit Tolerance Stackup Along X Axis: Option 2 Determine if the cover fits within the enclosure along X axis. Answer(答案): Min=0.6204, Max=4.3
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Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Exercise 10.3 Cover Fit Tolerance Stackup Along the Y Axis:: Option 2 Determine if the cover fits within the enclosure along Y axis.Answer(答案): Min=0.5376, Max=4.3
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Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Exercise 10.4 Screw Head Clearance Tolerance Stackup: Option 1 Determine if the cover contacts the M4 screw heads.Answer(答案): Min=-1.05, Max=3.33
Extra data: M4 washer thickness= 1.2± 0.1. M4 x 8 screw head height= 4/3.82
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Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Exercise 10.5 Ground Plate to Enclosure Gap Study: Option 1 Parts Determine if the ground plate contacts the inside walls of the enclosure.Answer(答案): Min=-0.23, Max=5.23
Extra data: M4 tapped hole Dims: Minor diameter=3.242-3.422. M4 x 8 socket head cap screw Dims: Major diameter 3.82-4.
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© Copyright 2008 Omnex–奥曼克公司
Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Exercise 10.6 Ground Plate to Enclosure Gap Study: Option 2 Determine if the ground plate contacts the inside walls of the enclosure.Answer(答案): Min=0.17, Max=4.83
Extra data: M4 tapped hole Dims: Minor diameter=3.242-3.422. M4 x 8 socket head cap screw Dims: Major diameter 3.82-4.
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© Copyright 2008 Omnex–奥曼克公司
Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Exercise 10.7 Ground Plate to Enclosure Gap Study: Option 3 Determine if the ground plate contacts the inside walls of the enclosure.Answer(答案): Min=1.11, Max=3.89
Extra data: M4 tapped hole Dims: Minor diameter=3.242-3.422. M4 x 8 socket head cap screw Dims: Major diameter 3.82-4.
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© Copyright 2008 Omnex–奥曼克公司
Chapter#10 Advanced Tolerance Stack-up (高级公差叠加)
Exercise#10.8计算A-B的最大最小距离Answer(答案): Min=228.32, Max=251.68
A
B
What’s possibility for this happening?42© Copyright 2008 Omnex–奥曼克公司
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