电子线路 非线性部分 第五版 谢嘉奎 课后答案

Po2(VCC2RL

C2VCE(sat))21.17W Po/PD94.36% 2-5

VVcm = 11 VVbm = 0.24 V

IcIm = 54 mAPDPoVCC = 12 VVBB = 0.5 iCIC0 = 32 mARe

(1)

vBE/V

vCE/V 0300 0.74 1 CEvBEVVBBcos(t)V0.24cos)V 12030 0.71 0.71 454.22 60 0.62 6.5 750.56 9.15 900.5 12 1200.38 17.5

(2)

VCCIC0384mW

1PoVcmIcm297mW 2

Po/PD77.34% Re = Vcm/Ic1m = 204 PD